Solid State Bedini Free Energy

[JoeLag]

Here is a concept I want to share:

https://youtu.be/mMcVGb_Lahg

In this post, I want to share with you a simple yet effective way to experiment with the back EMF radiant voltage spike, a concept John Bedini spoke of. With a big air core single coil and low voltage zero current pulsing, we can reproduce the same effects.

The idea behind this method is to trigger the high voltage back EMF voltage while holding back and gating the current. By keeping the spike sharp, we aim to use just pure voltage to save on energy usage or requiring very little input drive to produce this back EMF. We take this high voltage zero current radiant sharp spike and send it to two charging batteries hooked up in parallel.

To control the switching pulse width modulation, I use a simple tablet with software waveform generator, an analog sound card port output, and a control NPN switching transistor. The sound output from the tablet, set to a fast frequency of 2 kHz and tight duty cycle of 6 percent, triggers the base of the transistor to rapidly switch an input 9-volt battery, which is sent to a coil to collect the back EMF 30 plus high voltage radiant spike. The input battery doesn't "feel" it much, as we are limiting much of the current from leaving the input source.

This method allows us to achieve John Bedini's "get two for the price of one" trick without needing the wheel part. Even if you don't have a machine shop at the moment, you can still experiment with the Bedini process with this simple and effective method.

[tihomir]

Hi Joel,

First I want to say "Thank you" for the immense amount of work you have put into these videos and explaining your experiments in text as here.

Yesterday I found your YouTube channel and went back to the back-EMF experiments I've been doing a year ago, but without any success in utilizing it. I'm a self-taught amateur and I'm still struggling with many technical issues, although I think I understand the principles.  I've also found that all these have an exact relation to mechanical oscillators and work the same way, however, I still can't manage to figure out something from the back-EMF recycling.

I'll use the example with a simple low-side switching of a coil. In this video of yours you seem to be switching the coil with an NPN transistor on the high side. This is probably why your peaks get negative and you use a reversed diode. Is that correct?

In my tests I'm switching on the low side (just as Bedini and most of the NPN circuits) and the back-EMF peak is positive which is why I put the diode in a forward biased position right before the transistor (as a new branch). It's not working the other way (and it shouldn't be, in my opinion). I have the following:

(+) -------UUUUUUUU----o---(NPN)----(-)

At the "o" point between the coil and the NPN transistor I create a new branch with a diode to one leg of a capacitor.

--o--(NPN)-----(-)
  |
  |----------------------->|------------| capacitor | --------(?)

This is where I'm puzzled: what do I do with the other leg? If the first leg (let's call it) is the one with the peak, the other leg, at first I thought, should go to the "-". I did it that way, but nothing special happened. Yes, the capacitor gets charged, however, I can't feed it back to the input, because I don't know how.

In your explanation in another thread it seems that the "other leg" should go back to the "+". This sounds like "splitting the positive" (in the E.V. Gray motor) where we have a "+" that is "more positive" than another "+" and current can flow downhill. In this case the "other leg" of the capacitor should probably go back to the "+", the initial source? Maybe I have to put a diode between the "other leg" and the "+" so no current is fed back before the capacitor is charged?

But what do I do with the original minus when I turn the source off? Do I replace it with ground? I tested both ways with no success.

In order to test this I'm connecting a few LEDs in shunt to the capacitor using a potentiometer to limit the current draw. For a moment I thought it was working, but got disappointed when I found that the LEDs were dimming in about of 10-15 seconds.

I haven't calculated any coil or capacitor values. No resonance, just a random frequency with short duty cycle where I see back-EMF peaks on the oscilloscope . I'm using an air-core bifilar coil and a 50uF capacitor.

I had the same issue a year ago and could not resolve it. Could not find anyone to ask, because most "specialists" deny anything about the possibility of using the back-EMF for something useful, so I was on my own. Finding your YouTube channel gave me hope I could find the reason for my frustration. What is the mistake I'm making?

I hope I was somehow clear in my explanations.

[JoeLag]

Hi Joel,

First I want to say "Thank you" for the immense amount of work you have put into these videos and explaining your experiments in text as here.

Yesterday I found your YouTube channel and went back to the back-EMF experiments I've been doing a year ago, but without any success in utilizing it. I'm a self-taught amateur and I'm still struggling with many technical issues, although I think I understand the principles.  I've also found that all these have an exact relation to mechanical oscillators and work the same way, however, I still can't manage to figure out something from the back-EMF recycling.

I'll use the example with a simple low-side switching of a coil. In this video of yours you seem to be switching the coil with an NPN transistor on the high side. This is probably why your peaks get negative and you use a reversed diode. Is that correct?

In my tests I'm switching on the low side (just as Bedini and most of the NPN circuits) and the back-EMF peak is positive which is why I put the diode in a forward biased position right before the transistor (as a new branch). It's not working the other way (and it shouldn't be, in my opinion). I have the following:

(+) -------UUUUUUUU----o---(NPN)----(-)

At the "o" point between the coil and the NPN transistor I create a new branch with a diode to one leg of a capacitor.

--o--(NPN)-----(-)
  |
  |----------------------->|------------| capacitor | --------(?)

This is where I'm puzzled: what do I do with the other leg? If the first leg (let's call it) is the one with the peak, the other leg, at first I thought, should go to the "-". I did it that way, but nothing special happened. Yes, the capacitor gets charged, however, I can't feed it back to the input, because I don't know how.

In your explanation in another thread it seems that the "other leg" should go back to the "+". This sounds like "splitting the positive" (in the E.V. Gray motor) where we have a "+" that is "more positive" than another "+" and current can flow downhill. In this case the "other leg" of the capacitor should probably go back to the "+", the initial source? Maybe I have to put a diode between the "other leg" and the "+" so no current is fed back before the capacitor is charged?

But what do I do with the original minus when I turn the source off? Do I replace it with ground? I tested both ways with no success.

In order to test this I'm connecting a few LEDs in shunt to the capacitor using a potentiometer to limit the current draw. For a moment I thought it was working, but got disappointed when I found that the LEDs were dimming in about of 10-15 seconds.

I haven't calculated any coil or capacitor values. No resonance, just a random frequency with short duty cycle where I see back-EMF peaks on the oscilloscope . I'm using an air-core bifilar coil and a 50uF capacitor.

I had the same issue a year ago and could not resolve it. Could not find anyone to ask, because most "specialists" deny anything about the possibility of using the back-EMF for something useful, so I was on my own. Finding your YouTube channel gave me hope I could find the reason for my frustration. What is the mistake I'm making?

I hope I was somehow clear in my explanations.

Kind of difficult to understand your setup sitting from this angle. How ever if your convinced that your method generates a dc pulse. Back emf or other method. You can just isolate the output with a isolation transformer. Maybe a 10 to 10 windings to start with. Rectify the output of isolated side and send back into your dc input circuit.  Best of luck!

[tihomir]

Thanks, Joel.

Yes, I generate a series of short pulses from which I get the back EMF, charge a capacitor, and from there I'm stuck, because I was trying to connect the output of the capacitor to the input directly or with a diode. Of course, it's not working, because I've never tried to isolate the output from the input. I'm yet to see where the primary of the transformer should be, but I'll experiment.

Thanks for pointing this out. That's a golden nugget.

By the way, at times you refer to a "capacitor dump". As far as I understand, you mean periodical discharging of a charged capacitor using some kind of oscillator (spark gap, neon bulb, relaxation oscillator, etc.).

[JoeLag]

Thanks, Joel.

Yes, I generate a series of short pulses from which I get the back EMF, charge a capacitor, and from there I'm stuck, because I was trying to connect the output of the capacitor to the input directly or with a diode. Of course, it's not working, because I've never tried to isolate the output from the input. I'm yet to see where the primary of the transformer should be, but I'll experiment.

Thanks for pointing this out. That's a golden nugget.

By the way, at times you refer to a "capacitor dump". As far as I understand, you mean periodical discharging of a charged capacitor using some kind of oscillator (spark gap, neon bulb, relaxation oscillator, etc.).

Yeah as you pointed out there are various ways to trigger the "dump" one of my favorites is the neon SCR method like Bedini experimented with.

[tihomir]

Yeah as you pointed out there are various ways to trigger the "dump" one of my favorites is the neon SCR method like Bedini experimented with.

Thanks. I have to try the neon lamp one. I've only used a gas discharge diode, a spark gap (two bolts, but it requires very high voltages), and a transistor-based oscillator circuit. I have a feeling the gas discharge diode (used for arresting high-voltage peaks) limits the current and for this reason I'll compare it with the neon lamp method.

[tihomir]

I've just noticed that you are connecting the input point of the coil to the negative of the batteries and the back-EMF spike goes to the positive of the battery. This means the battery is charged with postive and more positive, i.e. with a voltage difference just like having a negative and positive. This is like having a DC offset and charging a battery this way. It's insteresting why not using the negative of the battery where the potential difference is greater.

I remember that Joseph Newman said in his book that in order to make a battery last longer we should prevent the positive getting to the negative as much as we can (meaning little current, more voltage). Not sure if this has any relation to that, but it's the first time I've noticed the two positives going into the battery.

I guess the same happens with charging the capacitors and capacitor banks when used instead of a battery.