diode cascade - Printable Version +- Forums (http://typeright.social/forum) +-- Forum: Electricity & Electronics (http://typeright.social/forum/forumdisplay.php?fid=3) +--- Forum: Alternative & Free Energy (http://typeright.social/forum/forumdisplay.php?fid=4) +--- Thread: diode cascade (/showthread.php?tid=506) |
diode cascade - freemind - 11-11-2024 Has anyone here ever chatted about a diode cascade? I asked ChatGPT a bit about it yesterday and got some interesting answers. The voltage at the output increases while maintaining the same input-output current. Since P=U*I, theoretically, a higher power output is possible at the output compared to the input. With a stepped cascade of 12V 12mA input, one could achieve several watts of gain. https://en.wikipedia.org/wiki/Voltage_multiplier Have I overlooked something? ChatGPT Part: The voltage at the output increases while maintaining the same input current. Since P=U*I, theoretically, a higher power output would be possible at the output compared to the input. With a stepped cascade of 12V 12mA input, one could achieve several watts of gain. If energy from the surroundings is introduced into the system, similar to how a heat pump works, this could explain the increased power output. RE: diode cascade - Andy - 11-11-2024 But how to "introduce " energy from surroundings to it? Don Smith also has schematics of several voltage multipliers in his papers. RE: diode cascade - freemind - 11-11-2024 (11-11-2024, 11:51 AM)Andy Wrote: But how to "introduce " energy from surroundings to it? I assume that some energy is coming from outside due to the principles. let's think about where that energy might come from. As a child, I experimented with high-voltage cascades, and I noticed that they became cooler at certain points. That might be the gain. Regarding the theory: The available current (A) remains the same at the input and output of the diode cascade. ChatGPT confirmed this for me. An Example. Let's say we have 12V voltage with a current of 120mA as an example. Cascade Input: 12V 120mA Formula: P = U * I , 1.44W = 12V * 120mA Cascade Output: 64V 120mA Formula: P = U * I , 5.52W = 64V * 120mA Therefore the gain is = 4.08W Of course, one must also consider the leakage currents of the diodes and the thermal losses in the model. Am I making a logical error with ChatGPT? RE: diode cascade - Andy - 11-11-2024 The same current at the beginning and at the end is internesting thing. I assumed that when voltage goes up, current goes down. If not in this case (in this multiplier), it sounds interesting. I know that ChatGPT sometimes talks nonsense. I am open to this new idea. I will also try to search in this direction. Andy Edit: I asked ChatGPT about it and here is the answer: "In a voltage multiplier circuit, like the Cockcroft-Walton multiplier or others, the voltage indeed increases at each stage while the available current decreases." RE: diode cascade - freemind - 11-11-2024 Thanks for checking. As you said, chat GPT is sometimes not entirely trustworthy (11-11-2024, 04:00 PM)Andy Wrote: The same current at the beginning and at the end is internesting thing. I assumed that when voltage goes up, current goes down. If not in this case (in this multiplier), it sounds interesting. I know that ChatGPT sometimes talks nonsense. I am open to this new idea. I will also try to search in this direction. |